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Toumeng
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« on: August 03, 2010, 08:27:05 PM » |
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I set both wife's watch and my watch at midnight. Later, I discovered that one of the watches went 2 minutes per hour too slow, and the other went 1 minute per hour too fast. When I looked at them later the same day, the faster one was exactly 1 hour ahead of the other.
What was the correct time when I looked at the watches?
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S.A.M.
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« Reply #1 on: August 09, 2010, 12:26:27 PM » |
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x = y/3
x = 60/3
x = 20
20 hours later = Time to bridenap wife number 3!
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Unlimited
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« Reply #2 on: August 25, 2010, 11:40:38 AM » |
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It's illegal to have 2 wives  |
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Cia koj rau tus koj hlub
Cia kuv nrog kuv txoj kev npam
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YAX
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« Reply #3 on: August 25, 2010, 11:47:21 AM » |
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only n the US.
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...And now a word to my Hmong Republicans. Are you sick and tired of poor people on welfare doing better than you? Hey! I got some news for you. If they're on welfare and they're doing better than you, you're amongst the poor and guess what? Mitt Romney doesn't care about you.
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NytWolf
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« Reply #4 on: August 25, 2010, 02:36:25 PM » |
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I set both wife's watch and my watch at midnight.
Why the hell you need to synchronize watches ... at midnight? You planning on a heist? |
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ToxicCum
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« Reply #5 on: August 25, 2010, 03:04:28 PM » |
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your wifes two watches are off....
but you set urs also....so urs went off at midnight...so the answer is 12am, that is the correct time...kuz ur watch didnt have a timing defect.
theres 3 watches involved
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Toumeng
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« Reply #6 on: September 27, 2010, 04:12:08 PM » |
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Haha.. okay sorry for the typo. It should be "I set my wife's watch and my watch.... " Not both or more than one wives.
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Reporter
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« Reply #7 on: September 28, 2010, 07:28:32 PM » |
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I'm not sure of what the mathematical formula is, but it sounds like for each minute or two that one watch falls behind, the other takes one more minute ahead. Finding their differences totally 60 minutes apart from the midnight time when the watches were set will get us the correct time when the setter relooked at them later that same day.
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Archipalego
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« Reply #8 on: September 28, 2010, 07:41:19 PM » |
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I'm not sure of what the mathematical formula is, but it sounds like for each minute or two that one watch falls behind, the other takes one more minute ahead. Finding their differences totally 60 minutes apart from the midnight time when the watches were set will get us the correct time when the setter relooked at them later that same day.
I was thinking of the same too. It would be 1 hour apart 60 hrs from now. It would be back to "midnight" same time; two and a half days later. |
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Toumeng
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« Reply #9 on: September 29, 2010, 11:07:18 AM » |
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I was thinking of the same too. It would be 1 hour apart 60 hrs from now. It would be back to "midnight" same time; two and a half days later.
Not quite. lol Reporter has the right idea on solving this problem. It's a mathematical problem.  |
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trepidpoda
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« Reply #10 on: October 01, 2010, 09:41:10 AM » |
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I set both wife's watch and my watch at midnight. Later, I discovered that one of the watches went 2 minutes per hour too slow, and the other went 1 minute per hour too fast. When I looked at them later the same day, the faster one was exactly 1 hour ahead of the other.
What was the correct time when I looked at the watches?
This sounds like an algebra equation: (x-2 min) + (x+1 min) = 60 minutes 2x-1 =60 2x =61 x=61/2 x= 30.5 Every 30.5 minutes (lets round it off), there is one minute difference It will take 20 hrs for the 60 minutes difference (1 hr); the time will be 8:00 pm when you checked. Just corrected; I missed added the 20 hrs after midnight.....i t is 8:00 pm. |
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« Last Edit: October 01, 2010, 03:15:07 PM by trepidpoda »
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« Reply #11 on: October 01, 2010, 10:33:42 AM » |
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Good. Sounds like the formula now. This sounds like an algebra equation:
(x-2 min) + (x+1 min) = 60 minutes
2x-1 =60
2x =61
x=61/2
x= 30.5
Every 30.5 minutes (lets round it off), there is one minute difference
It will take 20 hrs for the 60 minutes difference (1 hr); the time will be 6:00 pm when you checked.
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YAX
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« Reply #12 on: October 01, 2010, 11:33:55 AM » |
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wild guess.. midnight.
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...And now a word to my Hmong Republicans. Are you sick and tired of poor people on welfare doing better than you? Hey! I got some news for you. If they're on welfare and they're doing better than you, you're amongst the poor and guess what? Mitt Romney doesn't care about you.
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S.A.M.
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« Reply #13 on: October 01, 2010, 02:42:55 PM » |
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any sensible person would of seen that I already gave the formula and answer.
start with x = y / z
x = (in hours) the time past midnight.
y = (in mins) the amount of time the watches are apart.
z = (3) the constant. if every hour one watch is 1 min fast and the other 2 mins slow, that makes a 3 min difference every hour.
so the formula is: x = y / 3
your question gave us y (1 hour part). 1 hour = 60 mins
x(hours past midnight) = 60 / 3
x(hours past midnight) = 20
20 hours past midnight would be 8:00 PM
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« Last Edit: October 01, 2010, 02:44:45 PM by S.A.M. »
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trepidpoda
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« Reply #14 on: October 01, 2010, 03:25:48 PM » |
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Lets see what Toumeng say? The way how he described it looked algebraic.  |
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